1/9(4t-8)=1/18(t+8)

Solution for 1/9(4t-8)=1/18(t+8) equation:

1/9(4t-8)=1/18(t+8)

We move all terms to the left:

1/9(4t-8)-(1/18(t+8))=0


Domain of the equation: 9(4t-8)!=0

t∈R



Domain of the equation: 18(t+8))!=0

t∈R


We calculate fractions


(18tt/(9(4t-8)*18(t+8)))+(-9t4/(9(4t-8)*18(t+8)))=0


We calculate terms in parentheses: +(18tt/(9(4t-8)*18(t+8))), so:

18tt/(9(4t-8)*18(t+8))

We multiply all the terms by the denominator


18tt

Back to the equation:

+(18tt)



We calculate terms in parentheses: +(-9t4/(9(4t-8)*18(t+8))), so:

-9t4/(9(4t-8)*18(t+8))

We multiply all the terms by the denominator


-9t4

We add all the numbers together, and all the variables

-9t^4

We do not support etpression: t^4