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1/9(3-6x)=1/4(8+4x)
We move all terms to the left:
1/9(3-6x)-(1/4(8+4x))=0
Domain of the equation: 9(3-6x)!=0
x∈R
Domain of the equation: 4(8+4x))!=0We add all the numbers together, and all the variables
x∈R
1/9(-6x+3)-(1/4(4x+8))=0
We calculate fractions
(4x4/(9(-6x+3)*4(4x+8)))+(-9x0/(9(-6x+3)*4(4x+8)))=0
We calculate terms in parentheses: +(4x4/(9(-6x+3)*4(4x+8))), so:
4x4/(9(-6x+3)*4(4x+8))
We multiply all the terms by the denominator
4x4
We add all the numbers together, and all the variables
4x^4
We do not support expression: x^4
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