1/8x-3/4x=10

Solution for 1/8x-3/4x=10 equation:

1/8x-3/4x=10

We move all terms to the left:

1/8x-3/4x-(10)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We calculate fractions


4x/32x^2+(-24x)/32x^2-10=0

We multiply all the terms by the denominator


4x+(-24x)-10*32x^2=0

Wy multiply elements

-320x^2+4x+(-24x)=0

We get rid of parentheses

-320x^2+4x-24x=0

We add all the numbers together, and all the variables

-320x^2-20x=0

a = -320; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·(-320)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*-320}=\frac{0}{-640}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*-320}=\frac{40}{-640}
=-1/16
$