1/8(y+64)=1/4(20+2y)

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Solution for 1/8(y+64)=1/4(20+2y) equation: 



1/8(y+64)=1/4(20+2y)

We move all terms to the left:

1/8(y+64)-(1/4(20+2y))=0



Domain of the equation: 8(y+64)!=0

y∈R





Domain of the equation: 4(20+2y))!=0

y∈R



We add all the numbers together, and all the variables

1/8(y+64)-(1/4(2y+20))=0

We calculate fractions


(4y2/(8(y+64)*4(2y+20)))+(-8yy/(8(y+64)*4(2y+20)))=0



We calculate terms in parentheses: +(4y2/(8(y+64)*4(2y+20))), so:

4y2/(8(y+64)*4(2y+20))

We multiply all the terms by the denominator


4y2

We add all the numbers together, and all the variables

4y^2

Back to the equation:

+(4y^2)





We calculate terms in parentheses: +(-8yy/(8(y+64)*4(2y+20))), so:

-8yy/(8(y+64)*4(2y+20))

We multiply all the terms by the denominator


-8yy

Back to the equation:

+(-8yy)



We get rid of parentheses

4y^2-8yy=0

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