4(3/5y)+4y=140

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Solution for 4(3/5y)+4y=140 equation: 



4(3/5y)+4y=140

We move all terms to the left:

4(3/5y)+4y-(140)=0



Domain of the equation: 5y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

4(+3/5y)+4y-140=0

We add all the numbers together, and all the variables

4y+4(+3/5y)-140=0

We multiply parentheses

4y+12y-140=0

We add all the numbers together, and all the variables

16y-140=0

We move all terms containing y to the left, all other terms to the right

16y=140

y=140/16

y=8+3/4

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