1/8(d-2)=1/4(d+5)

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Solution for 1/8(d-2)=1/4(d+5) equation: 



1/8(d-2)=1/4(d+5)

We move all terms to the left:

1/8(d-2)-(1/4(d+5))=0



Domain of the equation: 8(d-2)!=0

d∈R





Domain of the equation: 4(d+5))!=0

d∈R



We calculate fractions


(4dd/(8(d-2)*4(d+5)))+(-8dd/(8(d-2)*4(d+5)))=0



We calculate terms in parentheses: +(4dd/(8(d-2)*4(d+5))), so:

4dd/(8(d-2)*4(d+5))

We multiply all the terms by the denominator


4dd

Back to the equation:

+(4dd)





We calculate terms in parentheses: +(-8dd/(8(d-2)*4(d+5))), so:

-8dd/(8(d-2)*4(d+5))

We multiply all the terms by the denominator


-8dd

Back to the equation:

+(-8dd)



We get rid of parentheses

4dd-8dd=0

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