-8+(2/3x)=x-5

Solution for -8+(2/3x)=x-5 equation:

-8+(2/3x)=x-5

We move all terms to the left:

-8+(2/3x)-(x-5)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3x)-(x-5)-8=0

We get rid of parentheses

2/3x-x+5-8=0

We multiply all the terms by the denominator


-x*3x+5*3x-8*3x+2=0

Wy multiply elements

-3x^2+15x-24x+2=0

We add all the numbers together, and all the variables

-3x^2-9x+2=0

a = -3; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·(-3)·2
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{105}}{2*-3}=\frac{9-\sqrt{105}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{105}}{2*-3}=\frac{9+\sqrt{105}}{-6}
$