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-8+2/3x=x-5
We move all terms to the left:
-8+2/3x-(x-5)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
2/3x-x+5-8=0
We multiply all the terms by the denominator
-x*3x+5*3x-8*3x+2=0
Wy multiply elements
-3x^2+15x-24x+2=0
We add all the numbers together, and all the variables
-3x^2-9x+2=0
a = -3; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·(-3)·2
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{105}}{2*-3}=\frac{9-\sqrt{105}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{105}}{2*-3}=\frac{9+\sqrt{105}}{-6} $
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