1/8(X-12)=2+x

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Solution for 1/8(X-12)=2+x equation: 



1/8(X-12)=2+X

We move all terms to the left:

1/8(X-12)-(2+X)=0



Domain of the equation: 8(X-12)!=0

X∈R



We add all the numbers together, and all the variables

1/8(X-12)-(X+2)=0

We get rid of parentheses

1/8(X-12)-X-2=0

We multiply all the terms by the denominator


-X*8(X-12)-2*8(X-12)+1=0

Wy multiply elements

-8X^2(X-16X(X+1=0

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