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7(x+3)+2=2x+5(4+x)
We move all terms to the left:
7(x+3)+2-(2x+5(4+x))=0
We add all the numbers together, and all the variables
7(x+3)-(2x+5(x+4))+2=0
We multiply parentheses
7x-(2x+5(x+4))+21+2=0
We calculate terms in parentheses: -(2x+5(x+4)), so:We add all the numbers together, and all the variables
2x+5(x+4)
We multiply parentheses
2x+5x+20
We add all the numbers together, and all the variables
7x+20
Back to the equation:
-(7x+20)
7x-(7x+20)+23=0
We get rid of parentheses
7x-7x-20+23=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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