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1/8(8y+4)-17=-1/2(4y-8)
We move all terms to the left:
1/8(8y+4)-17-(-1/2(4y-8))=0
Domain of the equation: 8(8y+4)!=0
y∈R
Domain of the equation: 2(4y-8))!=0We calculate fractions
y∈R
(2y4/(8(8y+4)*2(4y-8)))+(-(-8y8)/(8(8y+4)*2(4y-8)))-17=0
We calculate terms in parentheses: +(2y4/(8(8y+4)*2(4y-8))), so:
2y4/(8(8y+4)*2(4y-8))
We multiply all the terms by the denominator
2y4
We add all the numbers together, and all the variables
2y^4
We do not support eypression: y^4
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