1/8(8y+4)-17=-1/2(4y-8

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Solution for 1/8(8y+4)-17=-1/2(4y-8 equation: 



1/8(8y+4)-17=-1/2(4y-8

We move all terms to the left:

1/8(8y+4)-17-(-1/2(4y-8)=0



Domain of the equation: 8(8y+4)!=0

y∈R





Domain of the equation: 2(4y-8)-17!=0

We move all terms containing y to the left, all other terms to the right

2(4y-8)!=17

y∈R



We calculate fractions


(2y(4-17)/(8(8y+4)*2(4y-8)-17)+(-(-8y8)/(8(8y+4)*2(4y-8)-17)=0



We calculate terms in parentheses: +(2y(4-17)/(8(8y+4)*2(4y-8)-17)+(-(-8y8)/(8(8y+4)*2(4y-8)-17), so:

2y(4-17)/(8(8y+4)*2(4y-8)-17)+(-(-8y8)/(8(8y+4)*2(4y-8)-17

We add all the numbers together, and all the variables

(-(-8y^8)/(8(8y+4)*2(4y-8)-17+2y(-13)/(8(8y+4)*2(4y-8)-17)

We can not solve this equation

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