1/8(5m+64)=1/4(20+2m)

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Solution for 1/8(5m+64)=1/4(20+2m) equation: 



1/8(5m+64)=1/4(20+2m)

We move all terms to the left:

1/8(5m+64)-(1/4(20+2m))=0



Domain of the equation: 8(5m+64)!=0

m∈R





Domain of the equation: 4(20+2m))!=0

m∈R



We add all the numbers together, and all the variables

1/8(5m+64)-(1/4(2m+20))=0

We calculate fractions


(4m2/(8(5m+64)*4(2m+20)))+(-8m5/(8(5m+64)*4(2m+20)))=0



We calculate terms in parentheses: +(4m2/(8(5m+64)*4(2m+20))), so:

4m2/(8(5m+64)*4(2m+20))

We multiply all the terms by the denominator


4m2

We add all the numbers together, and all the variables

4m^2

Back to the equation:

+(4m^2)





We calculate terms in parentheses: +(-8m5/(8(5m+64)*4(2m+20))), so:

-8m5/(8(5m+64)*4(2m+20))

We multiply all the terms by the denominator


-8m5

We add all the numbers together, and all the variables

-8m^5

We do not support empression: m^5

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