1/8(4t-4)=1/16(t+4)

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Solution for 1/8(4t-4)=1/16(t+4) equation: 



1/8(4t-4)=1/16(t+4)

We move all terms to the left:

1/8(4t-4)-(1/16(t+4))=0



Domain of the equation: 8(4t-4)!=0

t∈R





Domain of the equation: 16(t+4))!=0

t∈R



We calculate fractions


(16tt/(8(4t-4)*16(t+4)))+(-8t4/(8(4t-4)*16(t+4)))=0



We calculate terms in parentheses: +(16tt/(8(4t-4)*16(t+4))), so:

16tt/(8(4t-4)*16(t+4))

We multiply all the terms by the denominator


16tt

Back to the equation:

+(16tt)





We calculate terms in parentheses: +(-8t4/(8(4t-4)*16(t+4))), so:

-8t4/(8(4t-4)*16(t+4))

We multiply all the terms by the denominator


-8t4

We add all the numbers together, and all the variables

-8t^4

We do not support etpression: t^4

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