X=(6+4)+(5+100x2)

Solution for X=(6+4)+(5+100x2) equation:

X=(6+4)+(5+100X^2)

We move all terms to the left:

X-((6+4)+(5+100X^2))=0

We add all the numbers together, and all the variables

-(10+(5+100X^2))+X=0


We calculate terms in parentheses: -(10+(5+100X^2)), so:

10+(5+100X^2)

determiningTheFunctionDomain
(5+100X^2)+10

We get rid of parentheses

100X^2+5+10

We add all the numbers together, and all the variables

100X^2+15

Back to the equation:

-(100X^2+15)


We add all the numbers together, and all the variables

X-(100X^2+15)=0

We get rid of parentheses

-100X^2+X-15=0

a = -100; b = 1; c = -15;
Δ = b2-4ac
Δ = 12-4·(-100)·(-15)
Δ = -5999
Delta is less than zero, so there is no solution for the equation