1/8(3y+10)=1/4(3y+2)

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Solution for 1/8(3y+10)=1/4(3y+2) equation: 



1/8(3y+10)=1/4(3y+2)

We move all terms to the left:

1/8(3y+10)-(1/4(3y+2))=0



Domain of the equation: 8(3y+10)!=0

y∈R





Domain of the equation: 4(3y+2))!=0

y∈R



We calculate fractions


(4y3/(8(3y+10)*4(3y+2)))+(-8y3/(8(3y+10)*4(3y+2)))=0



We calculate terms in parentheses: +(4y3/(8(3y+10)*4(3y+2))), so:

4y3/(8(3y+10)*4(3y+2))

We multiply all the terms by the denominator


4y3

We add all the numbers together, and all the variables

4y^3

We do not support eypression: y^3

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