117=1/2(2x+14)(x+3)

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Solution for 117=1/2(2x+14)(x+3) equation: 



117=1/2(2x+14)(x+3)

We move all terms to the left:

117-(1/2(2x+14)(x+3))=0



Domain of the equation: 2(2x+14)(x+3))!=0

x∈R



We multiply parentheses ..

-(1/2(+2x^2+6x+14x+42))+117=0

We multiply all the terms by the denominator


-(1+117*2(+2x^2+6x+14x+42))=0



We calculate terms in parentheses: -(1+117*2(+2x^2+6x+14x+42)), so:

1+117*2(+2x^2+6x+14x+42)

determiningTheFunctionDomain
117*2(+2x^2+6x+14x+42)+1

Wy multiply elements

234x(++1

We use the square of the difference formula

234x(+1

Back to the equation:

-(234x(+1)



We add all the numbers together, and all the variables

-(234x1=0

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