1/8(3x+44)=1/4(3x=7)

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Solution for 1/8(3x+44)=1/4(3x=7) equation: 



1/8(3x+44)=1/4(3x=7)

We move all terms to the left:

1/8(3x+44)-(1/4(3x)=0



Domain of the equation: 8(3x+44)!=0

x∈R





Domain of the equation: 43x!=0

x!=0/43

x!=0

x∈R



We calculate fractions


43x/(1032x^2+15136x)+(-8x3/(1032x^2+15136x)=0



We calculate terms in parentheses: +(-8x3/(1032x^2+15136x), so:

-8x3/(1032x^2+15136x

We multiply all the terms by the denominator


-8x3

We add all the numbers together, and all the variables

-8x^3

We do not support expression: x^3

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