-4(2x+1)-3(x+2)=3(4-x)+2

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Solution for -4(2x+1)-3(x+2)=3(4-x)+2 equation: 



-4(2x+1)-3(x+2)=3(4-x)+2

We move all terms to the left:

-4(2x+1)-3(x+2)-(3(4-x)+2)=0

We add all the numbers together, and all the variables

-4(2x+1)-3(x+2)-(3(-1x+4)+2)=0

We multiply parentheses

-8x-3x-(3(-1x+4)+2)-4-6=0



We calculate terms in parentheses: -(3(-1x+4)+2), so:

3(-1x+4)+2

We multiply parentheses

-3x+12+2

We add all the numbers together, and all the variables

-3x+14

Back to the equation:

-(-3x+14)



We add all the numbers together, and all the variables

-11x-(-3x+14)-10=0

We get rid of parentheses

-11x+3x-14-10=0

We add all the numbers together, and all the variables

-8x-24=0

We move all terms containing x to the left, all other terms to the right

-8x=24

x=24/-8

x=-3

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