1/7x+35=63

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Solution for 1/7x+35=63 equation: 



1/7x+35=63

We move all terms to the left:

1/7x+35-(63)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



We add all the numbers together, and all the variables

1/7x-28=0

We multiply all the terms by the denominator


-28*7x+1=0

Wy multiply elements

-196x+1=0

We move all terms containing x to the left, all other terms to the right

-196x=-1

x=-1/-196

x=1/196

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