1/7m=35

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Solution for 1/7m=35 equation: 



1/7m=35

We move all terms to the left:

1/7m-(35)=0



Domain of the equation: 7m!=0

m!=0/7

m!=0

m∈R



We multiply all the terms by the denominator


-35*7m+1=0

Wy multiply elements

-245m+1=0

We move all terms containing m to the left, all other terms to the right

-245m=-1

m=-1/-245

m=1/245

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