1/6x+7/42-x=4/5x-1

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Solution for 1/6x+7/42-x=4/5x-1 equation: 



1/6x+7/42-x=4/5x-1

We move all terms to the left:

1/6x+7/42-x-(4/5x-1)=0



Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R





Domain of the equation: 5x-1)!=0

x∈R



We add all the numbers together, and all the variables

-1x+1/6x-(4/5x-1)+7/42=0

We get rid of parentheses

-1x+1/6x-4/5x+1+7/42=0

We calculate fractions


1050x^2/5040x^2-1x+840x/5040x^2+(-4032x)/5040x^2+1=0

We multiply all the terms by the denominator


1050x^2-1x*5040x^2+840x+(-4032x)+1*5040x^2=0

We add all the numbers together, and all the variables

1050x^2+840x-1x*5040x^2+(-4032x)+1*5040x^2=0

Wy multiply elements

1050x^2-5040x^3+5040x^2+840x+(-4032x)=0

We get rid of parentheses

1050x^2-5040x^3+5040x^2+840x-4032x=0

We do not support expression: x^3

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