(X+3)(x+3)(x+3)(x+3)=28

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Solution for (X+3)(x+3)(x+3)(x+3)=28 equation: 



(X+3)(X+3)(X+3)(X+3)=28

We move all terms to the left:

(X+3)(X+3)(X+3)(X+3)-(28)=0

We multiply parentheses ..

(+X^2+3X+3X+9)(+X^2+3X+3X+9)-28=0

We move all terms containing X to the left, all other terms to the right

(+X^2+3X+3X+9)(+X^2+3X+3X+9)=28

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