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1/6x+2=-5/2x
We move all terms to the left:
1/6x+2-(-5/2x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 2x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
1/6x+5/2x+2=0
We calculate fractions
2x/12x^2+30x/12x^2+2=0
We multiply all the terms by the denominator
2x+30x+2*12x^2=0
We add all the numbers together, and all the variables
32x+2*12x^2=0
Wy multiply elements
24x^2+32x=0
a = 24; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·24·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*24}=\frac{-64}{48} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*24}=\frac{0}{48} =0 $
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