(2-6i)*(-4=3i)

Solution for (2-6i)*(-4=3i) equation:

(2-6i)(-4=3i)

We move all terms to the left:

(2-6i)(-4-(3i))=0

We add all the numbers together, and all the variables

(-6i+2)(-3i-4)=0

We multiply parentheses ..

(+18i^2+24i-6i-8)=0

We get rid of parentheses

18i^2+24i-6i-8=0

We add all the numbers together, and all the variables

18i^2+18i-8=0

a = 18; b = 18; c = -8;
Δ = b2-4ac
Δ = 182-4·18·(-8)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-30}{2*18}=\frac{-48}{36}
=-1+1/3
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+30}{2*18}=\frac{12}{36}
=1/3
$