1/6(x-5)=-4/5(x+2)

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Solution for 1/6(x-5)=-4/5(x+2) equation: 



1/6(x-5)=-4/5(x+2)

We move all terms to the left:

1/6(x-5)-(-4/5(x+2))=0



Domain of the equation: 6(x-5)!=0

x∈R





Domain of the equation: 5(x+2))!=0

x∈R



We calculate fractions


(5xx/(6(x-5)*5(x+2)))+(-(-24xx)/(6(x-5)*5(x+2)))=0



We calculate terms in parentheses: +(5xx/(6(x-5)*5(x+2))), so:

5xx/(6(x-5)*5(x+2))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)





We calculate terms in parentheses: +(-(-24xx)/(6(x-5)*5(x+2))), so:

-(-24xx)/(6(x-5)*5(x+2))

We multiply all the terms by the denominator


-(-24xx)

We get rid of parentheses

24xx

Back to the equation:

+(24xx)

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