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1/6(x+5)+5x=1/7x+4
We move all terms to the left:
1/6(x+5)+5x-(1/7x+4)=0
Domain of the equation: 6(x+5)!=0
x∈R
Domain of the equation: 7x+4)!=0We add all the numbers together, and all the variables
x∈R
5x+1/6(x+5)-(1/7x+4)=0
We get rid of parentheses
5x+1/6(x+5)-1/7x-4=0
We calculate fractions
5x+7x/(42x^2+210x)+(-6xx/(42x^2+210x)-4=0
We calculate fractions
We do not support expression: x^3
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