h+1=-(h/2)+5

Solution for h+1=-(h/2)+5 equation:

h+1=-(h/2)+5

We move all terms to the left:

h+1-(-(h/2)+5)=0

We add all the numbers together, and all the variables

h-(-(+h/2)+5)+1=0

We multiply all the terms by the denominator


h*2)+5)-(-(+h+1*2)+5)=0

We add all the numbers together, and all the variables

h*2)+5)-(-(h+2)+5)=0

We add all the numbers together, and all the variables

h*2)+5)-(-(h=0

Wy multiply elements

2h^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$h=\frac{-b}{2a}=\frac{0}{4}=0$