1/6(a+1)=1/4(2a-3)

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Solution for 1/6(a+1)=1/4(2a-3) equation:



1/6(a+1)=1/4(2a-3)
We move all terms to the left:
1/6(a+1)-(1/4(2a-3))=0
Domain of the equation: 6(a+1)!=0
a∈R
Domain of the equation: 4(2a-3))!=0
a∈R
We calculate fractions
(4a2/(6(a+1)*4(2a-3)))+(-6aa/(6(a+1)*4(2a-3)))=0
We calculate terms in parentheses: +(4a2/(6(a+1)*4(2a-3))), so:
4a2/(6(a+1)*4(2a-3))
We multiply all the terms by the denominator
4a2
We add all the numbers together, and all the variables
4a^2
Back to the equation:
+(4a^2)
We calculate terms in parentheses: +(-6aa/(6(a+1)*4(2a-3))), so:
-6aa/(6(a+1)*4(2a-3))
We multiply all the terms by the denominator
-6aa
Back to the equation:
+(-6aa)
We get rid of parentheses
4a^2-6aa=0

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