4(n-3)=2(n-2)

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Solution for 4(n-3)=2(n-2) equation: 



4(n-3)=2(n-2)

We move all terms to the left:

4(n-3)-(2(n-2))=0

We multiply parentheses

4n-(2(n-2))-12=0



We calculate terms in parentheses: -(2(n-2)), so:

2(n-2)

We multiply parentheses

2n-4

Back to the equation:

-(2n-4)



We get rid of parentheses

4n-2n+4-12=0

We add all the numbers together, and all the variables

2n-8=0

We move all terms containing n to the left, all other terms to the right

2n=8

n=8/2

n=4

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