1/6(48m-36)=1/2(16m+12)

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Solution for 1/6(48m-36)=1/2(16m+12) equation: 



1/6(48m-36)=1/2(16m+12)

We move all terms to the left:

1/6(48m-36)-(1/2(16m+12))=0



Domain of the equation: 6(48m-36)!=0

m∈R





Domain of the equation: 2(16m+12))!=0

m∈R



We calculate fractions


(2m1/(6(48m-36)*2(16m+12)))+(-6m4/(6(48m-36)*2(16m+12)))=0



We calculate terms in parentheses: +(2m1/(6(48m-36)*2(16m+12))), so:

2m1/(6(48m-36)*2(16m+12))

We multiply all the terms by the denominator


2m1

We add all the numbers together, and all the variables

2m

Back to the equation:

+(2m)





We calculate terms in parentheses: +(-6m4/(6(48m-36)*2(16m+12))), so:

-6m4/(6(48m-36)*2(16m+12))

We multiply all the terms by the denominator


-6m4

We add all the numbers together, and all the variables

-6m^4

We do not support empression: m^4

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