10d+4=6(4/3d+2

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Solution for 10d+4=6(4/3d+2 equation: 



10d+4=6(4/3d+2

We move all terms to the left:

10d+4-(6(4/3d+2)=0



Domain of the equation: 3d+2)+4!=0

d∈R



We multiply all the terms by the denominator


10d*3d+2)+4-(6(4=0

We add all the numbers together, and all the variables

10d*3d=0

Wy multiply elements

30d^2=0

a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{0}{60}=0$

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