1/6((3x-7)2-22)=x-6

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Solution for 1/6((3x-7)2-22)=x-6 equation: 



1/6((3x-7)2-22)=x-6

We move all terms to the left:

1/6((3x-7)2-22)-(x-6)=0



Domain of the equation: 6((3x-7)2-22)!=0

x∈R



We get rid of parentheses

1/6((3x-7)2-22)-x+6=0

We multiply all the terms by the denominator


-x*6((3x-7)2-22)+6*6((3x-7)2-22)+1=0

Wy multiply elements

-6x^2((+36x((+1=0

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