1/5x-2/3x-2=(x+4)=2

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Solution for 1/5x-2/3x-2=(x+4)=2 equation: 



1/5x-2/3x-2=(x+4)=2

We move all terms to the left:

1/5x-2/3x-2-((x+4))=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We calculate fractions


-((x+4))+3x/15x^2+(-10x)/15x^2-2=0



We calculate terms in parentheses: -((x+4)), so:

(x+4)

We get rid of parentheses

x+4

Back to the equation:

-(x+4)



We get rid of parentheses

-x+3x/15x^2+(-10x)/15x^2-4-2=0

We multiply all the terms by the denominator


-x*15x^2+3x+(-10x)-4*15x^2-2*15x^2=0

We add all the numbers together, and all the variables

3x-x*15x^2+(-10x)-4*15x^2-2*15x^2=0

Wy multiply elements

-15x^3-60x^2-30x^2+3x+(-10x)=0

We get rid of parentheses

-15x^3-60x^2-30x^2+3x-10x=0

We do not support expression: x^3

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