8-2(2-x)=4(x+2)

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Solution for 8-2(2-x)=4(x+2) equation: 



8-2(2-x)=4(x+2)

We move all terms to the left:

8-2(2-x)-(4(x+2))=0

We add all the numbers together, and all the variables

-2(-1x+2)-(4(x+2))+8=0

We multiply parentheses

2x-(4(x+2))-4+8=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

2x-(4x+8)+4=0

We get rid of parentheses

2x-4x-8+4=0

We add all the numbers together, and all the variables

-2x-4=0

We move all terms containing x to the left, all other terms to the right

-2x=4

x=4/-2

x=-2

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