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1/5x-1=1/3x-3
We move all terms to the left:
1/5x-1-(1/3x-3)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x-3)!=0We get rid of parentheses
x∈R
1/5x-1/3x+3-1=0
We calculate fractions
3x/15x^2+(-5x)/15x^2+3-1=0
We add all the numbers together, and all the variables
3x/15x^2+(-5x)/15x^2+2=0
We multiply all the terms by the denominator
3x+(-5x)+2*15x^2=0
Wy multiply elements
30x^2+3x+(-5x)=0
We get rid of parentheses
30x^2+3x-5x=0
We add all the numbers together, and all the variables
30x^2-2x=0
a = 30; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·30·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*30}=\frac{0}{60} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*30}=\frac{4}{60} =1/15 $
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