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1/5x+4/5x-3=25
We move all terms to the left:
1/5x+4/5x-3-(25)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x+4/5x-28=0
We multiply all the terms by the denominator
-28*5x+1+4=0
We add all the numbers together, and all the variables
-28*5x+5=0
Wy multiply elements
-140x+5=0
We move all terms containing x to the left, all other terms to the right
-140x=-5
x=-5/-140
x=1/28
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