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4x=282/7x+5=
We move all terms to the left:
4x-(282/7x+5)=0
Domain of the equation: 7x+5)!=0We get rid of parentheses
x∈R
4x-282/7x-5=0
We multiply all the terms by the denominator
4x*7x-5*7x-282=0
Wy multiply elements
28x^2-35x-282=0
a = 28; b = -35; c = -282;
Δ = b2-4ac
Δ = -352-4·28·(-282)
Δ = 32809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{32809}}{2*28}=\frac{35-\sqrt{32809}}{56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{32809}}{2*28}=\frac{35+\sqrt{32809}}{56} $
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