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1/5x+12=37
We move all terms to the left:
1/5x+12-(37)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x-25=0
We multiply all the terms by the denominator
-25*5x+1=0
Wy multiply elements
-125x+1=0
We move all terms containing x to the left, all other terms to the right
-125x=-1
x=-1/-125
x=1/125
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