If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/5x+1/2=5(2/3x+4)
We move all terms to the left:
1/5x+1/2-(5(2/3x+4))=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x+4))!=0We calculate fractions
x∈R
(-(5(2*5x*2)/15x^2+45x^2/15x^2+3x/15x^2=0
We can not solve this equation
| -8x+4(x+7)=20 | | n-7=43 | | 325x+x=10 | | x+x+7x=0 | | -9x+12x=3(2-x | | 3p^2-12p-96=0 | | 454,873+x÷3=215,325 | | 3p^-12p-96=0 | | 1-2t=2(1-t | | 3x=296 | | -5x+73=2x+11 | | 3q=4+3+q | | .7(–3y+2)=8(3y–2) | | 2x/5+6=6 | | x2+6x–160=0 | | 3(4h-1)=4(h+3) | | 3a−2a=14 | | 3r=-1+6 | | 1500000=150000x.03 | | -½x-18=72 | | 3s=1+s+3 | | 11r−r=20 | | 4(x+1)=6x+9) | | 3x-5+2x+7x=0 | | 7/8x-¼+1/2x=¾+x | | x^2-3/2x=7/16 | | 8x=-2-6 | | 5x=1160 | | 5b-4b+b-15=0 | | 4n2-12n+5=0 | | 9x2+4x-8=0 | | -8x2+40=0 |