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1/5q=9-(2/5)q
We move all terms to the left:
1/5q-(9-(2/5)q)=0
Domain of the equation: 5q!=0
q!=0/5
q!=0
q∈R
Domain of the equation: 5)q)!=0We add all the numbers together, and all the variables
q!=0/1
q!=0
q∈R
1/5q-(9-(+2/5)q)=0
We calculate fractions
5q/25q^2+(-(9-(+2*5q)/25q^2=0
We multiply all the terms by the denominator
5q+(-(9-(+2*5q)=0
We calculate terms in parentheses: +(-(9-(+2*5q), so:
-(9-(+2*5q
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-(9-(+2*5q
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-(9-(+2*5q
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-(9-(+2*5q
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-(9-(+2*5q
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-(9-(+2*5q
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-(9-(+2*5q
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| 2y-6y-9=0 | | 5x+6=9x-10* | | 1/2×-6=-28-1/4x | | 64x^2+80x-39=0 | | w/38=48 | | 5+3p–2+7p=-1-11p | | 4(3x-2=77 | | 2p=p*(1.08)T | | 2y2+14y+24=0 | | 2(5x-4)=7x-8 | | 19-(x=6)=4x-2 | | 5x+8+6x-5=180 | | -3x-9=3x+6 | | x-4+3=-9 | | X+5+6x+17=x/ | | 6y-6-3y+1=0 | | 2x-0=4x-29 | | (w/8)=(-12/32) | | 2x+4=-6x-2 | | (3/4)=(21/m+2) | | 3x+2+8=2 | | 4w+20=3w+25 | | 3x+2=26+9x | | 7v-5=-40 | | -x+28=18 | | 4x(2x+3)-7=53 | | -7x+25=60 | | -3x+12=39 | | 5x-4x=3x+8 | | (2x+2)*350=(0,6x+6)*350+3500 | | y2+3y=4y2 | | -2x=2+3x |