(w/8)=(-12/32)

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Solution for (w/8)=(-12/32) equation:



(w/8)=(-12/32)
We move all terms to the left:
(w/8)-((-12/32))=0
We add all the numbers together, and all the variables
(+w/8)-((-12/32))=0
We get rid of parentheses
w/8-((-12/32))=0
We calculate fractions
32w^2/()+()/()=0
We add all the numbers together, and all the variables
32w^2/()+1=0
We multiply all the terms by the denominator
32w^2+1*()=0
We add all the numbers together, and all the variables
32w^2=0
a = 32; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·32·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{64}=0$

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