1/5(x-2)=1/10(x=+6)

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Solution for 1/5(x-2)=1/10(x=+6) equation: 



1/5(x-2)=1/10(x=+6)

We move all terms to the left:

1/5(x-2)-(1/10(x)=0



Domain of the equation: 5(x-2)!=0

x∈R





Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R



We calculate fractions


10x/(50x^2-100x)+(-5xx/(50x^2-100x)=0



We calculate terms in parentheses: +(-5xx/(50x^2-100x), so:

-5xx/(50x^2-100x

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

10x/(50x^2-100x)-5xx=0

We multiply all the terms by the denominator


10x-5xx*(50x^2-100x)=0

We multiply parentheses

-250x^3+500x^2+10x=0

We do not support expression: x^3

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