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(3y+1)2=2(17-5y)
We move all terms to the left:
(3y+1)2-(2(17-5y))=0
We add all the numbers together, and all the variables
(3y+1)2-(2(-5y+17))=0
We multiply parentheses
6y-(2(-5y+17))+2=0
We calculate terms in parentheses: -(2(-5y+17)), so:We get rid of parentheses
2(-5y+17)
We multiply parentheses
-10y+34
Back to the equation:
-(-10y+34)
6y+10y-34+2=0
We add all the numbers together, and all the variables
16y-32=0
We move all terms containing y to the left, all other terms to the right
16y=32
y=32/16
y=2
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