1/5(x+2)=2/5(x+4)

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Solution for 1/5(x+2)=2/5(x+4) equation: 



1/5(x+2)=2/5(x+4)

We move all terms to the left:

1/5(x+2)-(2/5(x+4))=0



Domain of the equation: 5(x+2)!=0

x∈R





Domain of the equation: 5(x+4))!=0

x∈R



We calculate fractions


(5xx/(5(x+2)*5(x+4)))+(-10xx/(5(x+2)*5(x+4)))=0



We calculate terms in parentheses: +(5xx/(5(x+2)*5(x+4))), so:

5xx/(5(x+2)*5(x+4))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)





We calculate terms in parentheses: +(-10xx/(5(x+2)*5(x+4))), so:

-10xx/(5(x+2)*5(x+4))

We multiply all the terms by the denominator


-10xx

Back to the equation:

+(-10xx)



We get rid of parentheses

5xx-10xx=0

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