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16x-3(4x+7)=6x-(2x+2)
We move all terms to the left:
16x-3(4x+7)-(6x-(2x+2))=0
We multiply parentheses
16x-12x-(6x-(2x+2))-21=0
We calculate terms in parentheses: -(6x-(2x+2)), so:We add all the numbers together, and all the variables
6x-(2x+2)
We get rid of parentheses
6x-2x-2
We add all the numbers together, and all the variables
4x-2
Back to the equation:
-(4x-2)
4x-(4x-2)-21=0
We get rid of parentheses
4x-4x+2-21=0
We add all the numbers together, and all the variables
-19!=0
There is no solution for this equation
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