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1/5(5y+10)-8=-1/3(9y-18)
We move all terms to the left:
1/5(5y+10)-8-(-1/3(9y-18))=0
Domain of the equation: 5(5y+10)!=0
y∈R
Domain of the equation: 3(9y-18))!=0We calculate fractions
y∈R
(3y9/(5(5y+10)*3(9y-18)))+(-(-5y5)/(5(5y+10)*3(9y-18)))-8=0
We calculate terms in parentheses: +(3y9/(5(5y+10)*3(9y-18))), so:
3y9/(5(5y+10)*3(9y-18))
We multiply all the terms by the denominator
3y9
We add all the numbers together, and all the variables
3y^9
We do not support eypression: y^9
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