(3y-2)=(y+8)

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Solution for (3y-2)=(y+8) equation: 



(3y-2)=(y+8)

We move all terms to the left:

(3y-2)-((y+8))=0

We get rid of parentheses

3y-((y+8))-2=0



We calculate terms in parentheses: -((y+8)), so:

(y+8)

We get rid of parentheses

y+8

Back to the equation:

-(y+8)



We get rid of parentheses

3y-y-8-2=0

We add all the numbers together, and all the variables

2y-10=0

We move all terms containing y to the left, all other terms to the right

2y=10

y=10/2

y=5

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