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1/5(4x+9)=1+1x
We move all terms to the left:
1/5(4x+9)-(1+1x)=0
Domain of the equation: 5(4x+9)!=0We add all the numbers together, and all the variables
x∈R
1/5(4x+9)-(x+1)=0
We get rid of parentheses
1/5(4x+9)-x-1=0
We multiply all the terms by the denominator
-x*5(4x+9)-1*5(4x+9)+1=0
Wy multiply elements
-5x^2(4-5x(4+1=0
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