7x-(3x-4)=-2(2x-1)+10

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Solution for 7x-(3x-4)=-2(2x-1)+10 equation: 



7x-(3x-4)=-2(2x-1)+10

We move all terms to the left:

7x-(3x-4)-(-2(2x-1)+10)=0

We get rid of parentheses

7x-3x-(-2(2x-1)+10)+4=0



We calculate terms in parentheses: -(-2(2x-1)+10), so:

-2(2x-1)+10

We multiply parentheses

-4x+2+10

We add all the numbers together, and all the variables

-4x+12

Back to the equation:

-(-4x+12)



We add all the numbers together, and all the variables

4x-(-4x+12)+4=0

We get rid of parentheses

4x+4x-12+4=0

We add all the numbers together, and all the variables

8x-8=0

We move all terms containing x to the left, all other terms to the right

8x=8

x=8/8

x=1

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